Suggested: 7(y+3)-2x+2)=14 4(y-2)+3(x-3)=2 by substitution method - if x=√3+1/2 find the value of 4x^3+2x^2-8x+7 - 7(y+3)-2x+2)=14 4(y-2)+3(x-3)=2 by elimination method - 2x+3y=7 (a+b+1)x+(a+2 b+2)y=4(a+b)+1 - 3x+2/7+4(x+1)/5=2/3(2x+1) - x-2 x+2-16/3x+5=3-7/2x - 7(y+3)-2x+2)=144(y-2)+3(x-3)=2 - concentric with x2+y2+2x-4y=5 radius is 7 - 3/4(7x-1)-(2x-1-x/2)=x+3/2 - expand 2x^3+7x^2+x-1 in power of x-2 - 6(2x^2-3x-2) 8(4x^2+4x+1) 1 2(2x^2+7x+3) - x=1/2-√3 find the value of x^3-2x^2-7x+5 - 2x-3y-7x+2x-y+2 - expand 2x^3+7x^2+x-6 in powers of x-2 - 7x^(2)+2x+2 Browse related:
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